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If the charge on a capacitor is doubled,...

If the charge on a capacitor is doubled, the value of its capacitance C will be

A

Doubled

B

Halved

C

Remain the same

D

None of these

Text Solution

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The correct Answer is:
To solve the question regarding the effect of doubling the charge on a capacitor on its capacitance, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definition of Capacitance**: The capacitance \( C \) of a capacitor is defined as the ratio of the charge \( Q \) stored on the capacitor to the potential difference \( V \) across it. Mathematically, this is expressed as: \[ C = \frac{Q}{V} \] 2. **Consider the Effect of Doubling the Charge**: If the charge on the capacitor is doubled, we can denote the new charge as \( Q' = 2Q \). 3. **Relate Charge, Capacitance, and Voltage**: Using the definition of capacitance, we can express the new capacitance \( C' \) when the charge is doubled: \[ C' = \frac{Q'}{V'} \] Since \( Q' = 2Q \), we have: \[ C' = \frac{2Q}{V'} \] 4. **Determine the New Voltage**: The voltage \( V \) across a capacitor is related to the charge and capacitance by the equation: \[ V = \frac{Q}{C} \] If we double the charge, the new voltage \( V' \) can be expressed as: \[ V' = \frac{Q'}{C} = \frac{2Q}{C} \] 5. **Substituting for New Voltage**: Now substituting \( V' \) back into the equation for \( C' \): \[ C' = \frac{2Q}{\frac{2Q}{C}} = C \] 6. **Conclusion**: From the above steps, we find that the capacitance \( C' \) remains the same as the original capacitance \( C \). Therefore, if the charge on a capacitor is doubled, the value of its capacitance does not change. ### Final Answer: The value of the capacitance \( C \) remains the same.

To solve the question regarding the effect of doubling the charge on a capacitor on its capacitance, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definition of Capacitance**: The capacitance \( C \) of a capacitor is defined as the ratio of the charge \( Q \) stored on the capacitor to the potential difference \( V \) across it. Mathematically, this is expressed as: \[ C = \frac{Q}{V} ...
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