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A parallel plate capacitor has a plate a...

A parallel plate capacitor has a plate area of `50 cm^2` and plate separation of 1.0 cm. A potential difference of 200 volt is applied across the plates with air as the dielectric between plates. The battery is then disconnected and a piece of Bakelite of dielectric constant 4.8 inserted which fills the complete volume between the plates. The capacitance before and after inserting Bakelite are respectively

A

44pF, 211.2pF

B

4.4pF, 211.2pF

C

4.4pF, 21.21pF

D

21.12pF, 44pF

Text Solution

Verified by Experts

The correct Answer is:
C
`A= 50 cm^2 = 50 xx10^(-4) m^2 , d = 1 xx10^(-2) m`
V = 200 Volt
When battery is disconnected -
`k = 4.8`
Before, `C_(@)=(Aepsilon_0)/ d =(50 xx10^(-4)xx8.85 xx10^(-12))/(1xx10^(-2))=4.42` pF
After, `C=kC_(@) = 4.8 xx4.42 pF = 21.21 ` pF
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