Home
Class 12
PHYSICS
The terminals of a battery of emf V are ...

The terminals of a battery of emf V are connected to the two plates of a parallel plate capacitor. If the space between the plates of the capacitor is filled with an insulator of dielectric constant K, then :

A

`kE_0`

B

`E_0`

C

`E_0/k`

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
B
`E_0` = constant, Because of no disturbance in the battery connection. V = constant
Promotional Banner

Similar Questions

Explore conceptually related problems

A parallel plate capacitor of capacitance 10 muF is connected across a battery of emf 5 mV. Now, the space between the plates of the capacitors is filled with a deielectric material of dielectric constant K=5. Then, the charge that will flow through the battery till equilibrium is reached is

If the gap between the plates of a parallel plate capacitor is filled with medium of dielectric constant k=2 , then the field between them

The figure shows two identical parallel plate capacitors connected to a battery with the switch S closed. The switch is now opened and the free space between the plates of the capacitors is filled with a dielectric of dielectric constant(or relative permittivity) 3. Find the ratio of the total electrostatic energy stored in both capacitors before and after the introduction of the dielectric.

A parallel plate capacitar, of capacitance, 20 mu F , is connected to a 100 V supply. After some time, the battery is disconnected , and the space, between the plates of the capacitor is filled with a dielectric, of dielectric constant 5. Calculate the energy stored in the capacitar (i) before (ii)after dielectric has been put in between its plates.

A parallel plate capacitor with air between the plates has a capacitance C. If the distance between the plates is doubled and the space between the plates is filled with a dielectric of dielectric constant 6, then the capacitance will become.

Two parallel plate capacitors, each of capacitance 40 muF, are connected is series. The space between the plates of one capacitor is filled with a dielectric material of dielectric constant K =4. Find the equivalent capacitacne of the system.

A parallel plate capacitor of capacitance C is charged to a potential V and then disconnected with the battery. If separation between the plates is decreased by 50% and the space between the plates is filled with a dielectric slab of dielectric constant K=10 . then

Two parallel plate air filled capacitors each of capacitance C, are joined in series to a battery of emf V. The space between the plates of one of the capacitors is then completely filled up with a uniform dielectric having dielectric constant K. The quantity of charge which flows through the battery is -

A parallel plate capacitor is charged completely and then disconnected from the battery. IF the separation between the plates is reduced by 50% and the space between the plates if filled with a dielectric slab of dielectric constant 10, then the potential difference between the plates