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A system is shown in the figure. The tim...

A system is shown in the figure. The time period for small oscillations of the two bolcks will be :-

A

`4.5 xx10^(-6) J`

B

`2.25 xx10^(-6) J`

C

Zero

D

`9 xx10^(-6) J`

Text Solution

Verified by Experts

The correct Answer is:
B
`Q= 900 xx10^(-12) xx100 =9 xx10^(-8)C`
`U_i = (Q^2)/(2C_1)=(9xx9 xx10^(-16))/(2 xx900 xx10^(-12))=4.5 xx10^(-6)J`
`U_f = Q^2/(2C_1+C_2)=(9 xx9xx10^(-16))/(2 xx 1800 xx10^(-12))=2.25 xx10^(-6) J`
Loss of energy `=U_i -U_f = 2.25 xx10^(-6) J`
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