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Eight drops of mercury of equal radii po...

Eight drops of mercury of equal radii possessing equal charges combine to from a big drop. Then the capacitance of bigger drop compared to each individual small drop is

A

8 times

B

4 times

C

2 times

D

32 times

Text Solution

Verified by Experts

The correct Answer is:
C
Volume of 8 small drops = Volume of big drop
`8 xx4/3 pir^3 =4/3 piR^3 impliesR=2r`
As capacity is proportional to r, hence capacitance of bigger drop becomes 2 times.
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