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A parallel plate capacitor with air as t...

A parallel plate capacitor with air as the dielectric has capacitance C. A slab of dielectric constant K and having the same thickness as the separation between plates is introduced so as to fill one-fourth of the capacitor as shown in the figure. The new capacitance will be :

A

`(k+3) C/4`

B

`(k+2) C/4`

C

`(k+1) C/4`

D

`(kC)/4`

Text Solution

Verified by Experts

The correct Answer is:
A
`C_(eq) =C_1+C_2=((A/4)epsilon_0k)/d+(((3A)/(4))epsilon_0)/d`
`=(Aepsilon_0)/d [k/4+3/4] =C/4 (k+3)`
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