Home
Class 12
PHYSICS
A gang capacitor is formed by interlocki...

A gang capacitor is formed by interlocking a number of plates as shown in figure. The distance between the consecutive plates is 0.885 cm annd the overlapping area of the plates is 5 `cm^(2)`. The capacity of the unit is

A

`1.0`

B

4 pF

C

6.36 pF

D

12.72 pF

Text Solution

Verified by Experts

The correct Answer is:
B

`C_(eq)=(8Aepsilon_0)/(d)=(8xx5 xx10^(-4)xx8.85 xx10^(-12))/(0.885xx10^(-2))`
= 4pF
Promotional Banner

Similar Questions

Explore conceptually related problems

A parallel plate capacitor has a uniform electric field vec(E) in the space between the plates. If the distance between the plates is 'd' and the area of each plate is 'A' the energy stored in the capacitor is

Each plate of a parallel plate condenser has surface area of 5 cm^(2) . The distance between the plates is 2 mm. The dielectric constant of the medium between the plates is 5. Then the capacity of the condenser is (epsi_(0) = 8.85 xx 10^(-12) C^(2)//Nm^(2))

The capcity of a parallel plate condenser is 10 muF , when the distance between its plates is 8 cm . If the distance between the plates is reduced to 4 cm , then the capacity of this parallel plate condenser will be

A parallel plate capacitor has a uniform electric field E in the space between the the plates. If the distance between the plates is d and area of each plate is A, the energy stored in the capacitor is

The capacity of a parallel plate condenser is 15 mu F when the distance between its plates is 6 cm. if the distance between the plates is reduced to 2 cm, then the capacity of this prarallel condenser will be