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100 capacitors each having a capacity of...

`100` capacitors each having a capacity of `10 muF` are connected in parallel and are charged by a potential difference of `100 kV`. The energy stored in the capacitors and the cost of charging them, if electrical energy costs `108` paise per `kWh`, will be

A

`10^7` and 300 paise

B

`5 xx10^6` and 300 paise

C

`5 xx10^6` and 150 paise

D

`10^7` and 150 paise

Text Solution

Verified by Experts

The correct Answer is:
C
`C_(eq) = 100 xx10 = 100 muF, V = 100 xx10^3 ` Volt
`U=1/2CV^2 =1/2xx1000 xx10^(-6) xx10^(4) xx10^6`
`= 5 xx10^6 J`
Since, `3.6 xx10^(6) J` cost 108 paise
`:. 5 xx10^6 J` costs `108/(3.6 xx10^6) xx 5 xx10^6 = 150 ` paise
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