When key is open – `q_1=CE` [charge in steady state] When key is closed – `V_C = (2R)/(R+2R) E =2/3E` [potential difference across capacitor] `q_2 =2/3 CE` [charge in steady state] `impliesq_1/q_2 =3/2`
Similar Questions
Explore conceptually related problems
A planet of mass M moves along a circle around the Sun with velocity v=34.9km//s (relative to the heliocentric reference frame). Find the period of revolution of this planet around the Sun.
Reduction potentials of A,B,C and D are 0.8 V 0.79 V, 0.34 V and -2.37 V respectively which element displaces all the other three elements
Reduction potentials of four elements P, Q, R, S is -2.90V, 0.34V, 1.2V and -0.76V . The decreasing order of reducing power is
Reduction potentials of 4 metals A, B, C and D are - 1.66 V, + 0.34 V, + 0.80 V and -0.76 V. What is the order of their reducing power and reactivity ?
