Suppose that `1.0g` of hydrogen is separated into electrons and protons. Suppose also that the protons are placed at the earth's north pole and the electrons are placed at the south pole. What is the resulting compression force on earth? (Given that the radius of earth is 6400 km).

Answer

`5.10`

Explanation

Number of electrons or protons in 1.00g of hydrogen is
`n=2[(1)/(2)xx6.023xx10^(23)]=6.023xx10^(23)`
Magnitude of charge on north or South pole is
`q=n e=6.023xx10^(23)xx1.6xx10^(-19)=96368C`
`F=(kq^(2))/(r^(2))=(9xx10^(9)xx(96368)^(2))/((2xx6400xx10^(3))^(2))=5.10xx10^(5)N`
= 5.10 kN.