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A charged particle having a charge of -2...

A charged particle having a charge of `-2.0 xx 10^(-6) C` is placed close to a non-conducting plate having a surface charge density `4.0 xx 10^(-6) C m^(-2)`. Find the force of attraction between the particle and the plate.

Text Solution

Verified by Experts

The correct Answer is:
`0.45`
Here `q=-2xx10^(-6)C, sigma=4xx10^(-6)Cm^(-2)`
Field produced by charged particle, `E=(sigma)/(2epsilon_(0))`
Force of attraction between the charged particle and the plate.
`F=qE=(sigmaq)/(2epsilon_(0))`
`=(4xx10^(-6)xx2xx10^(-6))/(2xx8.85xx10^(-12))=0.45N`
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