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Two equal point charges are fixed at x=-...

Two equal point charges are fixed at `x=-a` and `x=+a` on the x-axis. Another point charge Q is placed at the origin. The change in the electrical potential energy of Q, when it is displaced by a small distance x along the x-axis, is approximately proportional to

A

x

B

`x^(2)`

C

`x^(3)`

D

`1//x`

Text Solution

Verified by Experts

The correct Answer is:
B

`DeltaU=U_(f)-U_(i)=2KqQ[(a)/(a^(2)-x^(2))-(1)/(a)]`
`=(2KqQx^(2))/((a^(2)-x^(2))a)" as "agtgtx`
`DeltaU=(2KqQx^(2))/(a^(3))implies DeltaUpropx^(2)`
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