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There is a uniform spherically symmetri...

There is a uniform spherically symmetric surface charge density at a distance `R_(0)` from the origin . The charge distribution is intially at rest and starts expanding because of mutual repulsion , the figure that repeesents best the speed V (r(t)) of the distribution as a function of its intantanradius R(t) is :

A

B

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D

Text Solution

Verified by Experts

The correct Answer is:
D
`U_(i)+K_(i)=U_(f)+K_(f)`
`(KQ^(2))/(2r_(0))+0=(KQ^(2))/(2r)+(1)/(2)mv^(2)`
`v^(2)=(KQ^(2))/(m)((1)/(r_(0))-(1)/(r))`
`v=sqrt((KQ^(2))/(m)((1)/(r_(0))-(1)/(r)))`
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