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The figure shows an experimental plot di...

The figure shows an experimental plot discharging of a capacitor in an `RC` circuit. The time constant of this circuit lies between:

A

150 sec and 200 sec

B

0 and 50 sec

C

50 sec and 100 sec

D

100 sec and 150 sec

Text Solution

Verified by Experts

The correct Answer is:
D
For discharging of an RC circuit,
`V=V_(0)e^(-t//tau)`
So, when `V=(V_(0))/(2)`
`(V_(0))/(2)=V_(0)e^(-t//tau)`
`l n(1)/(2)=-(t)/(tau)impliestau=(1)/(l n2)`
From graph when `V=(V_(0))/(2),t=100s`
`therefore tau=(100)/(l n2)=144.3sec`.
So, time constant `(tau)` lies between 100 and 150 sec.
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