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In the given circuit diagram when the cu...

In the given circuit diagram when the current reaches steady state in the circuit , the charge on the capacitor of capacitance C will be :

A

`CE(r_(1))/((r_(1)+r))`

B

CE

C

`CE(r_(1))/((r_(2)+r))`

D

`CE(r_(2))/((r+r_(2)))`

Text Solution

Verified by Experts

The correct Answer is:
D
At steady state
current in the circuit
`I=(E)/(r+r_(2))`
Potential difference across `AB=Ir_(2)`
`=(Er_(2))/(r+r_(2))`
charge on capacitor `CimpliesQ=C(DeltaV)_(AB)`
`Q=(CEr_(2))/(r+r_(2))`
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