Home
Class 12
PHYSICS
A parallel -plate capacitor of area A, p...

A parallel -plate capacitor of area `A`, plate separation `d` and capacitance `C` is filled with four dielectric materials having dielectric constant `k_(1), k_(2), k_(3)` and `k_(4)` as shown in the figure below. If a single dielectric materical is to be used to have the same capacitance `C` in this capacitor, then its dielectric constant `k` is given by

A

`(2)/(k)=(3)/(k_(1)+k_(2)+k_(3))+(1)/(k_(4))`

B

`(1)/(k)=(1)/(k_(1))+(1)/(k_(2))+(1)/(k_(3))+(3)/(2k_(4))`

C

`k=k_(1)+k_(2)+k_(3)+3k_(4)`

D

`k=(2)/(3)(k_(1)+k_(2)+k_(3))+2k_(4)`

Text Solution

Verified by Experts

The correct Answer is:
A

Circuit can be redrawn as

`(1)/(C)=(1)/(C_(1))+(1)/(C_(2))`
`(d)/(Ain_(0)k)=(1)/((A)/(3)in_(0)((k_(1)+k_(2)+k_(3)))/(d//2))+(1)/((Ain_(0)k_(4))/(d//2))`
`implies (2)/(k)=(3)/(k_(1)+k_(2)+k_(3))+(1)/(k_(4))`
Promotional Banner

Similar Questions

Explore conceptually related problems

A parallel plate capacitor of area A, plate separation d and capacitance C is filled with three different dielectric materials having dielectric constants k_1 k_2 and k_3 as shown in the following figure. If a single dielectric material is to be used to have the same capacitance C in this capacitor then its dielectric constant k is given by

A parallel plate capacitor of area A , plate separation d and capacitance C is filled with three different dielectric materials having dielectric constant K_(1),K_(2) and K_(3) as shown in fig. If a single dielectric material is to be used to have the same effective capacitance as the above combination then its dielectric constant K is given by :

A parallel plate capacitor of area A, plate separation d and capacitance C is filled with three different dielectric materials having dielectric constants k_1 , k_2 and k_3 as shown. If a single dielectric material is to be used to have the same capacitance C in this capacitor, then its dielectic constant k is given by

A parallel plate capacitor with square plates is filed with four dielectrics of dielectric constants K_(1),K_(2),K_(3),K_(4), arranged as shown in the figure. The effective dielectric constant K will be :

A parallel plate capacitor with plate area A & plate separation d is filled with a dielectric material of dielectric constant given by K=K_(0)(1+alphax). . Calculate capacitance of system: (given alpha d ltlt 1) .

An air capacitor of capacitance C plate area A and plate separation d has been filled with three dielectrics of constant k_(1)=3 , k_(2)=6 and k_(3)=4 as shown in figure . What is the new capacitance ?