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Voltage rating of a parallel plate capac...

Voltage rating of a parallel plate capacitor is 500V. Its dielectric can withstand a maximum electric field of `10^(6)V//m`. The plate area is `10^(-4)m^(2)`. What is the dielectric constant if the capacitance is 15pF? (given `in_(0)=8.86xx10^(-12)C^(2)//Nm^(2)`)

A

3.8

B

4.5

C

8.5

D

6.2

Text Solution

Verified by Experts

The correct Answer is:
C
`E=(V)/(d)=(VC)/(AKepsilon_(0))`
`K=(VC)/(Aepsilon_(0)E)=(500xx15xx10^(-12))/(10^(-4)xx10^(6)xx8.85xx10^(-12))=8.47`.
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