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A cube of side 'a' has point charges +Q ...

A cube of side 'a' has point charges +Q located at each of its vertices except at the origin where the charge is -Q. The electric field at the centre of cube is :

A

`(2Q)/(3sqrt(3)piepsilon_(0)a^(2))(hatx+haty+hatz)`

B

`(-Q)/(3sqrt(3)piepsilon_(0)a^(2))(hatx+haty+hatz)`

C

`(-2Q)/(3sqrt(3)piepsilon_(0)a^(2))(hatx+haty+hatz)`

D

`(Q)/(3sqrt(3)piepsilon_(0)a^(2))(hatx+haty+hatz)`

Text Solution

Verified by Experts

The correct Answer is:
C

We can replace `-Q` charge at origin by `+Q` and `-2Q`. Now due to `+Q` charge at every corner of cube. Electric field at center of cube is zero so now net electric field at center is only due to `-2Q` charge at origin
`vecE=(kqvecr)/(r^(3))=(1(-2Q)(a)/(2)(hatx+haty+hatz))/(4piepsilon_(0)((a)/(2)sqrt(3))^(3))`
`vecE=(-2Q(hatx+haty+hatz))/(3sqrt(3)pia^(2)epsilon_(0))`
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