Home
Class 12
PHYSICS
A certain charge Q is divided into two p...

A certain charge Q is divided into two parts q and (Q–q). How should the charges Q and q be divided so that q and (Q–q) placed at a certain distance apart experience maximum electrostatic repulsion ?

A

`Q=2q`

B

`Q=(q)/(2)`

C

`Q=4q`

D

`Q=3q`

Text Solution

Verified by Experts

The correct Answer is:
A

`F=(Kq_(1)q_(2))/(r^(2))=(K(q)(Q-q))/(r^(2))`
`(dF)/(dq)=0`
`Q-2q=0`
`Q=2q`.
Promotional Banner

Similar Questions

Explore conceptually related problems

A certain charge Q is divided at first into two parts, q and Q-q. later on the charges are placed at a certain distance. If he force of interaction between two charges is maximum, then

A certain charge Q is divided into two parts q and Q-q , wheich are then separated by a cetain distance. What must q be in terms of Q to maximum the electrostatic repulsion between the two charges?

A charge is divided into two charges q and (Q-q) .The value of q so that force between them is maximum is equal to

A charge Q is divided into two parts. Charge on each part is q. Also, Q//q=2 . What is the Columbic force between two charges q and q when both parts are placed certain distance apart?

A charge Q is divided into q and Q - q. If Q/q = x , such that repulsion between them is maximum, find x.

two charge +q and -q are situated at a certain distance. At the point exactly midway between them

A charge Q is divided into two parts q_(1) and q_(2) such that they experience maximum force of repulsion when separated by certain distance. The ratio of Q,q_(1) and q_(2) is

A charge Q is divided into two parts of q and Q -q . If the coulomb repulsion between them when they are separated is to be maximum, the ratio of Q/q should be

Two point metal charges -q and +2q are placed at a certain distance apart.Where should a third point charge be placed so that it is in equilibrium?