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The masses of the three wires of copper ...

The masses of the three wires of copper are in the ratio 1 : 3 : 5. And their lengths are in the ratio 5 : 3 : 1. the ratio of their electrical resistance is

A

`1:3:5`

B

`5:3:1`

C

`1:15:125`

D

`125:15:1`

Text Solution

Verified by Experts

The correct Answer is:
D
`R = (rho l)/A = (rho l^(2))/(Al) = (rho l^(2) xx "density")/("Volume x density") rArr R prop l^(2)/m`
`R_(1) : R_(2) :R_(3) = l_(1)^(2)/m_(1) : l_(2)^(2)/m_(2) : l_(3)^(2)/m_(3) = 25/1 : 9/3 : 1/5`
`rArr R_(1) : R_(2) : R_(3) = 25 : 3 :1/5 = 125 : 15 : 1`
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