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A wire of resistor R is bent into a circ...

A wire of resistor R is bent into a circular ring of radius r. Equivalent resistance between two points X and Y on its circumference, when angle XOY is a, can be given by-

A

`(Ralpha)/(4pi^(2)) (2pi - alpha)`

B

`R/(2pi)(2pi - alpha)`

C

`R(2pi - alpha)`

D

`(4pi)/(R alpha)(2pi - alpha)`

Text Solution

Verified by Experts

The correct Answer is:
A

Since, `I = rtheta =r alpha`
Length of arc. XWY = `r alpha`
Resistance of arc. XZY = `R/(2pir) xx ar = (Ralpha)/(2pi)`
Resistance of arc XZY `=R/(2pir) xx r(2pir) xx alpha r = (R alpha(2pi-alpha))/(4pi^(2))`
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