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Two wires of equal diameters of resistiv...

Two wires of equal diameters of resistivities `rho_(1)` and `rho_(2)` and length `x_(1)` and `x_(2)` respectively are joined in series. Find the equivalent resistivity of the combination.

A

`(rho_(1)l_(1) + rho_(2)l_(2))/(l_(1) + l_(2))`

B

`(rho_(1) l_(2) + rho_(2)l_(1))/(I_(1) - I_(2))`

C

`(rho_(1) l_(2) + rho_(2)l_(1))/(l_(1) + l_(2))`

D

`(rho_(1)l_(1) - rho_(2)l_(2))/(l_(1) - l_(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
`R_(eq) = R_(1) + R_(2) = (rho_(1)l_(1))/A + (rho_(2)l_(2))/A`
`rho = (rho_(1)l_(1)+rho_(2)l_(2))/(l_(1) + l_(2))`
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