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The current in the arm CD of the circuit...

The current in the arm CD of the circuit will be-

A

`i_(1) + i_(2)`

B

`i_(2) + i_(3)`

C

`i_(1) + i_(3)`

D

`i_(1) - i_(2) + i_(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
`i_(CD) = i_(2) + i_(3) = i_(1)`
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