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In the circuit shown in fig. the cell ha...

In the circuit shown in fig. the cell has emf 10V and internal resistance `1 Omega`

A

10

B

100

C

500

D

200

Text Solution

Verified by Experts

The correct Answer is:
B
For no current through galvanometer-
`[E_(1)/(500 + X)]X = E rArr (12/(500 + X))X = 2`
`rArr 12X = 1000 + 2X rArr X = 100 Omega`
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