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A battery of emf 8 V with internal resis...

A battery of emf 8 V with internal resistance `0.5Omega` is being charged by a 120 V dc supply using a series resistance of `15.5Omega`. The terminal voltage of the battery is

A

20.5 V

B

15.5 V

C

11.5 V

D

2.5 V

Text Solution

Verified by Experts

The correct Answer is:
C
`I = (120-8)/(15.5 + 0.5) = 112/16 = 14/2 A`

`V_(A) - 8 - 0.5 xx 14/2 = V_(B)`
`rArr V_(A) - V_(B) = 8 + 14/4 = 11.5` Volt
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