Two batteries of emf `E_1` and `E_2 (E_2 gt E_1)` and internal resistances `r_1` and `r_2` respectively are connected in parallel as shown in figure-

Options

A. Two equivalent emf `E_(eq)` of the two cells is between `E_1` and `E_2` , i.e., `E_(1) lt E_(eq) lt E_(2)`
B. The equivalent emf `E_("eq")` is smaller than `E_(1)`
C. The `E_eq` is given by `E_eq = E_1 + E_2` always
D. `E_eq` is independent of internal resistances `r_(1)` and `r_(2)`

Answer

A

Explanation

The equivalent emf of this combination is given by-
`E_(eq) = (E_(2)r_(1) + E_(1)r_(2)/(r_(1) + r_(2)))`
This suggest that the equivalent emf `E_(eq)` of the two cells is given by-
`E_(1) lt E_(eq) lt E_(2)`