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Two batteries of emf E1 and E2 (E2 gt E1...

Two batteries of emf `E_1` and `E_2 (E_2 gt E_1)` and internal resistances `r_1` and `r_2` respectively are connected in parallel as shown in figure-

A

Two equivalent emf `E_(eq)` of the two cells is between `E_1` and `E_2` , i.e., `E_(1) lt E_(eq) lt E_(2)`

B

The equivalent emf `E_("eq")` is smaller than `E_(1)`

C

The `E_eq` is given by `E_eq = E_1 + E_2` always

D

`E_eq` is independent of internal resistances `r_(1)` and `r_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
The equivalent emf of this combination is given by-
`E_(eq) = (E_(2)r_(1) + E_(1)r_(2)/(r_(1) + r_(2)))`
This suggest that the equivalent emf `E_(eq)` of the two cells is given by-
`E_(1) lt E_(eq) lt E_(2)`
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Knowledge Check

  • Two batteries of emf epsi_1 and epsi_2 (epsi_2 gt epsi_1) and internal resistances r__1 and r_2 respectively are connected in parallel as shown in Fig. Then

    A
    the equivalent emf `epsi_(eq)` of the two cells is between`epsi_1` and `epsi_2` i.e., `epsi_1 lt epsi_(eq) lt epsi_2`
    B
    the equivalent emf `epsi_(eq)` is smaller than `epsi_1`
    C
    the `epsi_(eq)` is given by `epsi_(eq) = epsi_1 + epsi_2` always .
    D
    `epsi_(eq)` is independent of internal resistances `r_1` and `r_2`

  • Two batteries of emf epsi_(1) and epsi_(2)(epsi_(2) gt epsi_(1)) and internal resistance r_(1) and r_(2) respectively are connected in parallel as shown in figure.

    A
    The equivalent emf `epsi_(eq)` of the two cells is between `epsi_(1) and epsi_(2)`, i.e., `epsi_(1) lt epsi_(eq) lt epsi_(2)`
    B
    the equivalent emf `epsi_(eq)` is smaller than `epsi_(1)`
    C
    The `epsi_(eq)` is given by `epsi_(eq)=epsi_(1)+epsi_(2)` always.
    D
    `epsi_(eq)` is independent of internal resistance `r_(1) and r_(2)`.

  • Two batteries of emf epsilon_(1) and epsilon_(2) (epsilon_(2)gtepsilon_(1) and internal resistances r_(1) and r_(2) respectively are connected in parallel as shown in Fig. 2 (EP).1.

    A
    The equivalent emf `epsilon_(eq)` of the two cells is between `epsilon_(1)` and `epsilon_(2), i.e., epsilon_(1)ltepsilon_(eq)ltepsilon_(2)`
    B
    The quivalent emf `epsilon_(eq)` is smaller than `epsilon_(1)`
    C
    The `epsilon_(eq)` is given by `epsilon_(eq)=epsilon_(1)+epsilon_(2)` always
    D
    `epsilon_(eq)` is independent of internal resistances `r_(1)` and `r_(2)`