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In the circuit shown, the current throug...

In the circuit shown, the current through the `5 Omega` resistor is-

A

`8/3 A`

B

`9/13 A`

C

`4/13 A`

D

`1/3 A`

Text Solution

Verified by Experts

The correct Answer is:
D

`E_(eq) = (E_(1)r_(2) +E_(2)r_(1))/(r_(1) + r_(2)) = 2V, r_(eq) = 2/2 = 1 Omega, I = 2/6 = 1/3 A`
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