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A battery having e.m.f. 5 V and internal...

A battery having e.m.f. 5 V and internal resistance `0.5 Omega` is connected with a resistance of `4.5 Omega` then the voltage at the terminals of battery is

A

4.5 V

B

4 V

C

0 V

D

2 V

Text Solution

Verified by Experts

The correct Answer is:
A
`V = E-Ir = 5- (5/(4.5 + 0.5)) xx 0.5 rArr V = 4.5 `volt
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