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Two batteries A and B each of e.m.f. 2 V...

Two batteries A and B each of e.m.f. 2 V are connected in series to an external resistance R = 1 ohm . If the internal resistance of battery A is 1.9 ohms and that of B is 0.9 ohm , what is the potential difference between the terminals of battery A

A

2 V

B

3.8 V

C

Zero

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
C

`I = 4/(1.9 + 0.9 + 1) = 4/3.8 A`
`V_(A) = 2-1.9 xx 4/3.8 = 0`
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