Home
Class 12
PHYSICS
A Wheatstone bridge has the resistances ...

A Wheatstone bridge has the resistances `10 Omega, 10 Omega, 10 Omega` and `30 Omega` in its four arms. What resistance joined in parallel to the `30 Omega` resistance will bring it to the balanced condition

A

`2 Omega`

B

`5 Omega`

C

`10 Omega`

D

`15 Omega`

Text Solution

Verified by Experts

The correct Answer is:
D

`10/10 = ((30R)/(30 + R))/10`
`rArr 10 = (30R)/(30 + R)`
`rArr R = 15 Omega`
Promotional Banner

Similar Questions

Explore conceptually related problems

Four resistances 5 Omega, 5 Omega, 8 Omega and 10 Omega form a Wheatstone network. Find the resistance whch connected across the 10 Omega resistance will balance the network.

In Wheatstone bridge, the resistances in four arms are 10Omega,10Omega,10Omega and 20Omega . To make the bridge balance, resistance connected across 20Omega is

For resistances 10Omega, 10 Omega, 10 Omega and 15 Omega form a Wheatstone's network. What shunt is required across 15 Omega resistor to balance the bridge ?

Four resistances 6Omega,6Omega,6Omega and 18Omega form a Wheatstone bridge. Find the resistance which connected across the 18Omega resistance will balance the network.

The resistance of the four arms of a Wheatstone bridge are P= 10Omega , Q = 100Omega , R= 40Omega and S =10Omega . What resistance in series or parallel with the last one will be required to obtain no deflection in the galvanometer?

For resistances arranged to form a wheatstone's network are 10 Omega, 15 Omega, 6 Omega and 36 Omega . What resistance should be connected across the 36 Omega resistance to balance the bridge ?

The resistance of the four arms A, B, C and D of a wheatstone bridge as shown in the figure are 10 Omega , 20 Omega , 30 Omega and 60 Omega respectively . The emf and internal resistance of the cell are 15 V and 2.5 Omega respectively . If the galvanometer resistance is 80 Omega then the net current drawn from the cell will be

In a Wheatstone bridge circuit, P=5 Omega, Q=6 Omega, R=10 Omega and S= 5 Omega . Find the additional resistance to be used in series with S, so that the bridge is balanced.

In Wheatstone bridge, four resistors of resistances 15 Omega, 12 Omega, 4Omega and 10 Omega respectively, are connected in cyclic order. The resistance ( in Omega ) that is to be connected in parallel with the resistance of 10 Omega to balance the network is

Compare the heat developed in the four arms of a balanced. Wheatstone bridge. The resistance of the arms are 10Omega ,100Omega,40Omega and 400Omega . Also indicate in which arm the heat produced will be the minimum and in which the maximum.