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In a meter bridge experiment, resistance...

In a meter bridge experiment, resistances are connected as shown in figure. The balancing length `l_(1)=55cm`. Now, an unknown resistance x is connected in series with P and the new balancing length is found to be 75 cm. What is the value of The value of 11x (in ohm)? (Given, `P=4Omega`)

A

`54/12 Omega`

B

`20/11 Omega`

C

`48/11 Omega`

D

`11/48 Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
For the given meter bridge
`P/Q = I_(1)/(100 - I_(1)`
`I_(1) = 55 cm rArr 100 - I_(1) = 45 cm`
`therefore P = 3Q`
`rArr Q = 3 xx 45/55 = 3 xx 9/11 = 27/11 Omega`
When x is connected in series with `P, l_(1) = 75 cm`
`rArr (P + x)/Q = (75 cm)/(25 cm) rArr 3 + x = 3 xx 27/11`
`rArr x = 81/11 -3 rArr x = 48/11 Omega`
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