Home
Class 12
PHYSICS
A wire of length 100 cm is connected to...

A wire of length 100 cm is connected to a cell of emf 2 V and negligible internal resistance. The resistance of the wire is `3 Omega`. The additional resistance required to produce a potential drop of 1 milli volt per cm is

A

`60 Omega`

B

`47 Omega`

C

`57 Omega`

D

`35 Omega`

Text Solution

Verified by Experts

The correct Answer is:
C

`l = 2/(3 + R)`
`V/L = 1/100 ((2 xx 3)/(3 + R)) rArr 10^(-3) = 1/100 (6/(3 + R))`
`rArr 3 + R =60 rArr R = 57 Omega`
Promotional Banner

Similar Questions

Explore conceptually related problems

A 10 m long wire ofresistance 20 Omega is connected in series with battery of EMF 3V and negligible internal resistance and a resistance of 10 Omega . The potential gradient along the wire is :

A cell of e.m.f. 2 V and negligible internal resistance is connected to a potentiometer wire of resistance 10 Omega and length 4 m. The potential difference per unit length (potential gradient ) of the wire is

A wire of length 1.6m has a resistance 8 Omega is connected to a battery of 2 volts and internal resistance 2Omega . What is the potential gradient ?

A uniform potentiometer wire AB of length 100 cm has a resistance of 5Omega and it is connected in series with an external resistance R and a cell of emf 6 V and negligible internal resistance. If a source of potential drop 2 V is balanced against a length of 60 cm of the potentiometer wire, the value of resistance R is

A potentiometer wire has length 10 m and resistance 20Omega . A 2. 5 V battery of negligible internal resistance is connected across the wire with an 80 Omega series resistance. The potential gradient on the wire will be

A thin copper rod of radius 1mm having an electrical resistance of 100 Omega is connected to battery of emf 12 volts and negligible internal resistance through a wire of negligible resistance. Calculate current density in the wire. Also , calculate the number of electrons entering one and of the rod per seconds.

A potentiometer wire of length 1m and resistance 10 Omega is connected in series with a cell of emf 2V with internal resistance 1 Omega and a resistance box including a resistance R. If potential difference between the ends of the wire is 1 mV, the value of R is

A potentiometer wire of lengthh 100 cm has resistance 5Omega . It is connected in series with a resistance and a cell of emf 2 v and of negligible internal resistance. A source of emf 5 mv balanced by 10 cm length of potentiometer wire. The value of external resistance is___

A cell of emf 2 volt and internal resistance 1.5 Omega is connected to the ends of 1 m long wire. The resistance of wire is 0.5 Omega/m . Find the value of potential gradient on the wire.