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A potentiometer wire of length 1m and re...

A potentiometer wire of length 1m and resistance `10 Omega` is connected in series with a cell of emf 2V with internal resistance `1 Omega` and a resistance box including a resistance R. If potential difference between the ends of the wire is 1 mV, the value of R is

A

`20000 Omega`

B

`19989 Omega`

C

`10000 Omega`

D

`9989 Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
`V =IR =(2/(1 + 10 + R)) xx 10`

`rArr 10^(-3) = 20/(11 +R)`
`rARr R = 19989 Omega`
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