When the number of turns of the coil is doubled, the current sensitivity of a moving coil galvanometer is doubled whereas the voltage sensitivity of the galvanometer

Options

A. Remains the same
B. Is halved
C. Is doubled
D. Is quadrupled

Answer

A

Explanation

Current sensitivity `(phi/l) = (NAB)/K`
Voltage sensitivity `(phi/V) = (NAB)/(KR)`
`phi/V prop N` and `phi/V prop 1/R`
If `N. = 2N` then `R.= 2R`
`phi/V = (NAB)/(KR)` = remains constant.