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In the following circuit, 18Omega resist...

In the following circuit, `18Omega` resistor develops 2J/sec due to current flowing through it. The power developed across `10Omega` resistance is

A

125 W

B

10 W

C

`4/5` W

D

25 W

Text Solution

Verified by Experts

The correct Answer is:
B
`i_(1)/i_(2) = 9/18 = 1/2 rArrr I = i_(1)+i_(2)`
`P =i^(2)R rArr P_(10)/P_(18) =(i/i_(1))^(2) xx 10/18 rArr P_(10 Omega) = 10 W`
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