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A coil of wire of resistance 50 Omega is...

A coil of wire of resistance `50 Omega` is embedded in a block of ice. If a potential difference of 210 V is applied across the coil, the amount of ice melted per second will be

A

4.12 g

B

4.12 kg

C

3.68 kg

D

2.625 kg

Text Solution

Verified by Experts

The correct Answer is:
D
`Q/t =v^(2)/(4.2 R) = (mL)/t`
`m/t V = V^(2)/(4.2 RL) = (210)^(2)/(4.2 xx 50 xx 80) = 2.625 g`
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