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A fuse wire with radius 1 mm blows at 1....

A fuse wire with radius 1 mm blows at `1.5` amp . The radius of the fuse wire of the same material to blow at 3 A will be

A

`4^(1//3)` ohm

B

`3^(1/4)` ohm

C

`2^(1/2)` ohm

D

`3^(1//2)` ohm

Text Solution

Verified by Experts

The correct Answer is:
A

Fuse law-
`I prop r^(3//2) rArr r_(2)/r_(1) = (i_(2)/i_(1))^(2/3) = (3/1.5)^(2//3) = (4)^(1/3)`
`rArr r_(2) = 4^(1/3) xx r_(1) = 4^(1/3) mm`
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