In the circuit shown, the current in the...

In the circuit shown, the current in the `1 Omega` resistor is

A

1.3 A, from P to Q

B

12

C

0.13A, from Q to P

D

0.13 A, from P to Q

Verified by Experts

The correct Answer is:

C

`(x-6)/3 + (x-0)/1 + (x+9)/5=0`
`x(5+15 + 3)/15 = 2-9/5 = 1/5`
`x = 3/23`
`I =(x-0)/1 = 3/23 = 0.13 A`
From Q to P

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