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Two batteries with emf 12V and 13V are c...

Two batteries with emf 12V and 13V are connected in parallel across a load resistor of `10Omega`. The internal resistances of the two batteries are `1 Omega and 2 Omega` respectively. The voltage across the load lies between

A

11.4 V and 11.5 V

B

11.7 V and 11.8 V

C

11.6 V and 11.7 V

D

11.5 V and 11.6 V

Text Solution

Verified by Experts

The correct Answer is:
D

`r_(eq) = (1 xx 2)/(1 + 2) = 2/3 Omega`
`E_(eq) = (E_(1)/r_(1) + E_(2)/r_(2))/(1/r_(1) + 1/r_(2)) = (12/1 + 13/2)/(1/1 + 1/2) = 12.33 V`
`therefore V_(AB) = 12.33 xx 10/(10 + 2/3) = 11.55 V`
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