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In a Wheatstone bridge (see fige ) Res...

In a Wheatstone bridge (see fige ) Resitances P and Q are approximately equal .When `R= 400 Omega` the bridge is blanced .on is inerchanging P and Q ,the value of R, for balance is 405 `Omega ` .The value of X is close to :

A

404.5 ohm

B

402.5 ohm

C

403.5 ohm

D

401.5 ohm

Text Solution

Verified by Experts

The correct Answer is:
B
Initially
`P/Q = R_(1)/X`
After interchanging P and Q
`Q/P =R_(2)/X`
From (i) and (ii)
`1 = (R_(1) R_(2))/X^(2)`
`X = sqrt(R_(1) R_(2))`
`= sqrt(400 xx 405) = 402.5 Omega`
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