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A moving coil galvanometer, having a res...

A moving coil galvanometer, having a resistance G, produces full scale deflection when a current Ig flows through it. This galvanometer can be converted into
(i) An ammeter of range 0 to `I_(0)(I_(0)gtI_(g))` by connecting a shunt resistance `R_(A)` to it and
(ii) Into a voltmeter of range 0 to `V(V=GI_(0))` by connecting a series resistance `R_(V)` to it. Then

A

`R_(A)R_(V) = G^(2)((I_(0)-I_(g))/I_(g))` and `R_(A)/R_(V) =(I_(g)/(I_(0)-I_(g)))^(2)`

B

`R_(A)R_(V) = G^(2)` and `R_(A)/R_(V) = I_(g)/(I_(0)-I_(g))`

C

`R_(A)R_(V) = G^(2)` and `R_(A)/R_(V) =I_(g)/(I_(0)-I_(g))^(2)`

D

`R_(A)R_(V) = G^(2)(I_(g))/(I_(0)-I_(g))` and `R_(A)/R_(V) =((I_(0)-I_(g))/I_(g))^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`(I_(0)-I_(G))R_(A) = I_(G)G` and `V_(0) = I_(G)(G + R_(V))`
`I_(0) = (I_(G)(G + R_(A)))/R_(A), V_(0) = I_(G)(G +R_(V))`
`R_(A)G + R_(V)R_(A) = G^(2) +R_(A)G`
`R_(V)R_(A) = G^(2)`
`R_(A)G + R_(V)R_(A) = G^(2) + R_(A)G`
`R_(A)/R_(V) = I_(G)^(2)/(I_(0)-I_(G))^(2)`
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