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A magnetised wire of moment M is bent in...

A magnetised wire of moment M is bent into an arc of a circle subtending an angle of 60^(@) at the centre. The new magnetic moment is

A

`(2M//pi)`

B

`(M//pi)`

C

`(3 sqrt3M//pi)`

D

`(3M//pi)`

Text Solution

Verified by Experts

The correct Answer is:
D
`"sin" (theta)/(2)= (x)/(r)`
`rArr x= r "sin" (theta)/(2)`

New magnetic moment `M.= m(2x)= m 2 r "sin" (theta)/(2)`
`= m (2l)/(theta)."sin"(theta)/(2)= (2ml "sin"(theta)/(2))/(theta)= (2M sin ((pi)/(6)))/((pi)/(3))= (3M)/(pi)`
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