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A bar magnet of length 10cm and having t...

A bar magnet of length `10cm` and having the pole strength equal to `10^(-3)` weber is kept in a magnetic field having magnetic induction (B) equal to `4pixx10^(-3)` Tesla. It makes an angle of `30^(@)` with the direction of mwgnetic induction. The value of the torque acting on the magnet is
`(mu_(0)=4pixx10^(-7) weber//ampxxm)`

A

`2pi xx 10^(-7) N xx m`

B

`2pi xx 10^(-5) N xx m`

C

`0.5 N xx m`

D

`0.5 xx 10^(2) N xx m`

Text Solution

Verified by Experts

The correct Answer is:
A
`q_(m)= 10^(-3) wb, l= 0.1m, B= 4pi xx 10^(-3)T`
`theta= 30^(@)`
`tau= mB sin theta= q_(m)l B sin 30^(@)`
`= 10^(-3) xx 0.1 xx 4pi xx 10^(-3) xx (1)/(2) = 2pi xx 10^(-7) Nm`
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