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48.A bar magnet of "10cm" long is kept w...

48.A bar magnet of "10cm" long is kept with its "N" -pole pointing north A neutral point is formed at a distance of "15cm" from each pole.Given the horizontal component of Earth's field is "0.4Gauss" ,The pole strength of the magnet is

A

9 A- m

B

6.75 A-m

C

27 A-m

D

1.35 A-m

Text Solution

Verified by Experts

The correct Answer is:
D

`OP= sqrt(225- 25) = sqrt200`
`B_(H)= (mu_(0))/(4pi) (M)/((OP^(2) + AO^(2))^(3//2))`
`rArr M= (0.4 xx 10^(-4))/(10^(-7)) xx (225 xx 10^(-4))^(3//2)`
`rArr M= 1.35 A m`
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