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Two short magnets of equal dipole moment...

Two short magnets of equal dipole moments M are fastened perpendicularly at their centre (figure). The magnitude of the magnetic field at a distance d from the centre on the bisector of the right angle is

A

`(mu_(0))/(4pi) (M)/(d^(3))`

B

`(mu_(0))/(4pi) (M sqrt2)/(d^(3))`

C

`(mu_(0))/(4pi) (2 sqrt2M)/(d^(3))`

D

`(mu_(0))/(4pi) (2M)/(d^(3))`

Text Solution

Verified by Experts

The correct Answer is:
C
`M_("net") = sqrt(M^(2) + M^(2))= sqrt2M`
Point P lies on the axial line of the magnet
`B= (mu_(0))/(4pi).(2 sqrt2M)/(d^(3))`
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