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A domain in a ferromagnetic substance is...

A domain in a ferromagnetic substance is in the form of a cube of side length 1 `mu`m. If it contains `8 xx 10^(10)` atoms and each atomic dipole has a dipole moment of `9 xx 10^(-24) Am^(2)`, then magnetization of the domain is

A

`7.2 xx 10^(5) A m^(-1)`

B

`7.2 xx 10^(3) A m^(-1)`

C

`7.2 xx 10^(9) A m^(-1)`

D

`7.2 xx 10^(12) A m^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Volume = `(10^(-6))^(3)= 10^(=-18) m^(3)`
Net deipole moment-
`m_("net") = 8 xx 10^(10) xx 9 xx 10^(-24)`
`= 72 xx 10^(-14) A m^(2)`
Magnetization `M= (m_("net"))/("Volume") = (72 xx 10^(-14))/(10^(-18))`
`=72 xx 10^(4)= 7.2 xx 10^(5) A//m`
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