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A circular coil of 100 turns and having ...

A circular coil of `100` turns and having a radius of `0*05m` carries a current of `0*1A`. Calculate the work required to turn the coil in an external magnetic field of `1*5T` through `180^@` about an axis perpendicular to the magnetic field. The plane of the coil is initially at right angles to the magnetic field.

Text Solution

Verified by Experts

The correct Answer is:
`0.24`

Here , n = 100 , r = 0.05 m I = 0.1 A
W = ? B = 1.5 T ,
`theta_(1)=0^(@)` (when plane of coil is at `90^(@)` to B )
`theta_(2) = 180^(@)`
M = NIA = NI `(pi r^(2))`
`= 100 xx 0.1 (3.14) (0.05)^(2) = 7.85 xx 10^(-2) "Am"^(2)`
` W = - MB (cos theta_(2)-cos theta_(1))`
` = - 7.85 xx 10^(-2) xx 1.5 (cos 180^(@) - cos 0^(@)) = 0.24 J `
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