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Two short bar magnets of length 1cm each...

Two short bar magnets of length `1cm` each have magnetic moments `1.20 Am^(2) and 1.00 Am^(2)` respectively. They are placed on a horizontal table parallel to each other with their `N` poles pointing towards the south. They have a common magnetic equator and are separted by a distance of `20.0 cm`. The value of the resultant horizontal magnetic induction at the mid - point `O` of the line joining their centres is close to (Horizontal component of earths magnetic induction is `3.6 xx 10.5 Wh//m^(2)`

A

`3.6 xx 10^(-5) Wb//m^(2)`

B

`2.56 xx 10^(-4) Wb//m^(2)`

C

`3.50 xx 10^(-4) Wb//m^(2)`

D

`5.80 xx 10^(-4) Wb//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`M_(1)=1.2 "Am"^(2)`
`M_(2)= 1.0 " Am"^(2)`
` r = 20/2 cm = 0.1 m `

`B_("net") = B_(1) +B_(2) +B_(H)`
`=(mu_(0))/(4pi) ((M_(1)+M_(2)))/(r^(3)) +B_(H) =(10^(-7)xx(1.2+1))/((0.1)^(3)) +3.6 xx 10^(-5)`
`= 2.56 xx 10^(-4) "Wb/m"^(2)`
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