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A magnetic needle of magnetic moment 6*7...

A magnetic needle of magnetic moment `6*7xx10^-2Am^2` and moment of inertia `7*5xx10^-6kgm^2` is performing simple harmonic oscillations in a magnetic field of `0*01T`. Time taken for 10 complete oscillation is

A

8.76 s

B

6.65 s

C

8.89 s

D

6.98 s

Text Solution

Verified by Experts

The correct Answer is:
B
`M = 6.7 xx 10^(2) A-m^(2)`
`I = 7.5 xx 10^(-6) "kgm"^(2)`
`T = 2pi sqrt(I/(MB))=2pisqrt((7.5 xx 10^(-6))/(6.7 xx 10^(-2)xx10^(-2)))`
`= 2pisqrt((7.5)/(6.7)xx10^(-2))=2pi xx 10^(-1) sqrt((75)/(67))`
`t = 10 T = 2pi sqrt((75)/(67))= 6.65 ` sec
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