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A bar magnet of length 14 cm is placed i...

A bar magnet of length 14 cm is placed in the magnetic meridian with its north pole pointing towards the geographic north pole. A neutral point is obtained at a distance of 18 cm from the center of the magnet. If` B_(H)=0.4 G, `the magnetic moment of the magnet is `(1G = 10 ^(-4) T)`

A

`28.80 " JT"^(-1)`

B

`2.880 "J "T^(-1)`

C

`2.880 xx 10^(3) " JT"^(-1)`

D

`2.880 xx 10^(2) " JT"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`(2mu_(0))/(4pi) m/(r^(2))xx7/r = 0.4 xx 10^(-4)`
`rArr 2xx10^(-7) xx (m xx7)/((7^(2)+18^(3//2)))xx10^(4)=0.4 xx 10^(-4)`
`m = (4 xx 10^(-2) xx(373)^(3//2))/14`
`rArr M = m xx 14 cm = m xx 14/100 = 2.88 J//T `
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